Casino Games Online › Lottery › Ten Spot Keno

Keno can be very versatile in terms of pay table and house edge. Also, it depends largely on the maximum number of spots that players can choose and attempt to "hit" or "catch". It is typically limited to 10, 12 or 15 numbers (spots), but it can also be 20 numbers right away. One thing is always the same, there are 20 winning numbers drawn out of the total 80. Let us put the most typical 10-Spot Keno variation under the microscope and follow some concrete calculations.

This web page is a follow-up to the general Keno rules. Of course you can find there some interesting calculations as well. This time we pick up the most typical Keno variation with 10 spots. Thus the top prize is paid out if a player manages to guess 10 numbers out of the 20 numbers drawn.

Having chosen a **Ten Spot Keno** game, we can now calculate all the true odds and probabilities that are valid for this type of game. We will also use some model or possible pay table, which is the last element to enable us calculate the house edge (based on this model pay table). As the pay tables vary from casino to casino, so does the house edge.

Let us start with the pay table. Table 1 shows the payout ratios (the multiples) for all combinations of spots and successful hits. If you e.g. tried to catch 10 numbers and succeeded to hit them all, you would receive $200,000 for a $1 ticket. If you were less successful and hit "only" 9 of 10, the win would be $10,000 and so on. You can see that if you attempted to hit 10 to 6 numbers and hit no number, your bet would be returned.

The color key is simple. The payouts in green are winning, those in bright red are losing. The same logic is used for the remaining tables related to probability, odds and house edge as well.

Table 1 – A model 10-spot Keno pay table

Note: The model pay table was actually borrowed from the Czech lottery game Šťastných 10 (meaning "Lucky 10" in English), which is virtually a ten spot Keno game that fits perfectly for our needs. **The calculations of odds and probabilities below are 100% valid for any ten spot Keno game.** The model pay table will also be used demonstrate the calculation of the house edge (see Table 4, but let us not skip over).

The **probabilities for all combinations of spots and hits** are shown at the Table 2. It is a very valuable source of information. First of all, as always, the total of probabilities in a column must equal one (or 100% if you like). Then you can see, which outcomes are the most probable. For instance if you chose to catch 10 numbers, the most probable outcome would be hitting 2 numbers out of 10 (`0.2953`

or `29.53%`

to be exact).

You can also sum up the green values in a column to arrive at a winning (or actually "not losing" probability, because if you manage to catch zero numbers your bet will only be returned), in case of the 10-spot ticket it is `0.1105`

or `11.05%`

. Now you can sum up the red values or deduct the winning probability from 1 or 100% and you get the probability to lose `0.8895`

or `88.95%`

.

Table 2 – Ten spot Keno probabilities

For an exhibit we can calculate the probability of the least probable outcome, that is to catch all 10 numbers out of 10 (please note that for space purposes there are only 7 digits displayed in the Table 2). We already know that probability can be defined as the number of positive possibilities (the nominator) divided the total number of possibilities (the denominator).

It is easier to determine all possibilities (combinations) – they are the same for all-spot Keno games. We may use the Excel function `=COMBIN(80,20)`

and get the result of `3,535,316,142,212,180,000`

combinations (the denominator). To calculate the number of all winning possibilities is a bit harder as we have to catch 10 numbers out of 10, but there are 20 winning numbers drawn out of 80. Thus, with the use of Excel, the nominator is the following: `=COMBIN(10,10)*COMBIN(80-10,20-10) = 396,704,524,216`

.

Now we can put it together and calculate **the probability to get the top prize in ten spot Keno**. That is so close to zero that it is almost impossible:

`396,704,524,216 ÷ 3,535,316,142,212,180,000 = 0.000000112211895134156 or 0.0000112211895134156%`

.

You may think that the standalone probabilities in the Table 2 are not enough to decide whether they are that good or that bad. And you would be right. They need to be matched with the payouts. That is the only fair way to assess it and that is actually how the house edge is being calculated. But let us not jump forward.

First we can have a look at Table 3, the odds. They are just another and perhaps better-arranged presentation of the probabilities (the relation is: Odds = One divided Probability).

Table 3 – Ten spot Keno odds or the probability in the format "1 in ..."

The **calculation of house edge in ten spot Keno** is simpler as it seems. We will determine it based on the concept of expected value. We will take the net payouts from the Table 4 and the probabilities from the Table 2. The procedure to arrive at the expected outcome is as follows: the net payouts are simply multiplied (weighted) by the probabilities and added up.

Table 4 – Ten spot Keno net payouts (considering the $1 invested in the game)

Let us take e.g. a ten spot column as an example and suppose we bet a dollar. We may win `$199,999`

netto with the probability `0.000000112211895134156`

, so the partial expected outcome is `199,999 × 0.000000112211895134156 = approx. 0.0224`

(see the coordinates 10×10 in the Table 5). Now we slide a row down, that is to hitting 9 out of 10 and the net win `$9,999`

with the probability `0.0000061`

and the next partial expected outcome is approx. `0.0612`

(due to rounding) and so on. Then we add up all partial results and get the value `–0.5016`

or `–50.16%`

. That is quite high compared to Craps for instance (<2%).

Table 5 – Ten spot Keno house edge

The expected outcome for a player is *negative*. It is no surprise as it is the essence of all gambling and lottery games. House gets what a player loses—that is where the house edge comes from. Thus if you played 10 spot Keno with this pay table (Table 1), then, in the long run, you would likely lose about 50 cents per each dollar wagered in the game.

It is needed to highlight, however, that the expected value is related to the long-term period and that it does not mean that you could not be lucky enough to win the top prize with your first Keno ticket. It is just a lottery. You mostly lose, but if you win it is usually worth it.

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